At the casino I normally go to, playing the outside of the roulette wheel min bet is $15 and can’t be divided up between squares, unlike the inside. I usually place an insurance bet of $15 and a double up bet of $30 on the outside. Making it $45 per spin.
I’ve found after trial and error 6 spins is my sweet spot for beginning my cycle of betting so if I can’t hit how I want by then, I leave. 6×45=270.
Ok so to better explain. Roulette wheel has 38 possible outcomes. 1-36 and 0/00. Betting the outside comes with different odds, of course. I bet the dozens (1-12, 13-24, 25-36), giving me a 31.57% chance of hitting a single bet with a payout of 2:1.
Now, as I mentioned, I place two outside bets ($15 and $30.) I’ll place $15 on one of the dozens and $30 on a different dozen in the same line, meaning I only bet one type of dozen at a time (vertical being 1, 4, 7 etc. or horizontal being classic 1-12.)
This now gives me a 63.16% chance of hitting numbers that I have bet on. The purpose of the second bet is it is my “insurance bet”. If my small stack hits, I get my $15 dollar bet back, win $30 off that bet and lose my $30 big stack, essentially breaking even. If I hit my big stack, I get my $30 bet back, win $60 and lose my $15 small stack, essentially doubling the money I had on the board to begin with ($45).
Rinse and repeat until you hit a benchmark, which for me is where you double the total amount of money you walked in with (that $270) meaning you now have $540 worth of chips. To accelerate the process, I then double my betting ratios, meaning I begin betting $30/$60.
If I lose my first bet at that higher ratio, I drop back down to $15/$30 until I hit that benchmark again. If you double up again, hitting $1080, you double up your ratios and begin betting $60/$120.
Rinse and repeat.
Edit: Spelling
2nd Edit: Explanation.